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200 g mass of a certain metal at 83°C is immersed in 300 g of water at 30°C. The final temperature becomes 33°C. Calculate the specific heat capacity of

the metal.


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Heat lost by metal = Heat gained by water
200 \times c \times (83-33) = 300 \times 4.2 \times (33-30)

Hence c = 0.378 J/(g °C)

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