Answers

2015-06-12T13:10:35+05:30
f(x)= x^2-5x+1\\ \\f(2)= 2^2-5 \times 2+1 = 4-10+1=-5\\ \\f(-1)= (-1)^2-5(-1)+1=1+5+1=7\\ \\f( \frac{1}{3} )= (\frac{1}{3})^2-5(\frac{1}{3})+1=\frac{1}{9}-\frac{5}{3}+1 = \frac{1-15+9}{9}=-\frac{5}{9}\\ \\f(2)-f(-1)+f(1/3) = -5-7-\frac{5}{9}= \frac{-45-63-5}{9} =- \frac{113}{9}
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than u soooooo muck...u r really genius