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The acceleration due to gravity on the surface of moon is 1.7 m s^-2 .

What is the time period of a simple pendulum on the surface of the
moon, if its period on the Earth is 3.5 s ?


T = 2pi(l/g)^1/2
T2/T1 = (g1/g2)^1/2
T2/3.5 = (9.8/1.7)^1/2
T2 = 8.4s. 
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