Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let us consider two right triangles ABC and PQR where sin B = sin Q we have sin B = AC/AB and sin Q = PR/PQ AC/AB = PR/PQ then, AC/PR = AB/PQ = k , say _____________ (i) Now Using Pythagoras Theorem , BC = √AB² - AC² QR = √PQ² - PR² So, BC/QR = √AB² - AC² / √PQ² - PR² = √K²PQ² - K²PR² / √PQ² - PR² = k _____ (ii) FROM (i) and (ii) , we have AC/PR = AB/PQ = BC/QR Then by using theorem ΔACB ≈ ΔPRQ And therefore <B = < Q