Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions

A vehicle moves at a speed of 40km/h,It is stopped by applying brakes which produces a uniformaccelaration of-0.6m/s2. how much distance will the vehicle

move before coming to sle


Frnd here the initial velocity(u)is 40km/hr as the body at firts was moving with that speed where as the final velocity will be(v)will be 0 as the body tends to stop after the breakes are applied .Acceteration is negative which also results only when the final velocity is less than the initial velocity .here u can evaluate v-u/t= -0.6m/2s or -0.3m/s .but first change 40km/hr to m/s i.e100m/9s.get time and use the formula s=ut+1/2at sqaure. Or simply u can use the formula v square-u square=2as frm here u can get the value of s(distance) which will be the easiest
0 0 0
Pls buddy mark me as the best if u like my answer if u hav any doubt then ask me on inbox ..btw i was happy to help u buddy
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts