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2015-06-16T16:01:10+05:30

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S = u t +  \frac{1}{2} a t^{2}

Assume velocity at the starting of the 6th sec is "u"
24 = u (1) + \frac{1}{2} a (1)^{2}

Velocity at the starting of 11th sec 
v= u + at \\ v = u + a (11-6) \\ v = u + 5a

Therefore
44 = (u + 5a)(1) + \frac{1}{2} a (1)^{2}

Subtracting both the displacement equations 
a = 4
u (at the beginning of the 6th sec) = 22

For u ( at t = 0)
v=u+at \\ 22 = u + (4)(5) \\ u = 2

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