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Please solve and Define......

10ml of a solution of Nacl containing kcl on evaporation 0.93of the mixed salt which gave 1.865g of AgCl by reacting with AgNO3.Calculate the quantity of NaCl in 10ml of solution....


The Brainliest Answer!
NaCl + AgNO3 -----> NaNO3 + AgCl
Mol. wt of AgCl = 108+35.5=143.5
Mol. wt of NaCl = 23+35.5=58.5
143.5 g of AgCl is produced when 58.5 g of NaCl reacts
1.865 g of AgCl is produced when 58.5/143.5 * 1.865 =0.76 g of NaCl reacts

Ans. 0.76g of NaCl
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