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A car travelling at 36 km/hr due north turns west in 5 s under constant accelerationand maintains the same speed. the acceleration of the car is




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Initial velocity of car = 36 km/hr due north 
Final velocity of car = 36 km/hr due west

magnitude of change in velocity =  \sqrt{ 36^{2} + 36^{2} } = 36 \sqrt{2}
(since velocity is a vector, so direction has to be taken into account)

Acceleration =  \frac{Change\ in\ velocity}{time}  \frac{36 \sqrt{2} \times  \frac{5}{18} }{5} = 2.828\ m/s^2

(5/18 converts km/hr to m/s)
1 5 1
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