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Let S = set of points inside the square, T = the set of points inside the triangle and C = the set of points inside the circle. If the triangle and circle

intersect each other and are contained in a square. Then
(A) S ∩ T ∩ C = φ
(B) S ∪ T ∪ C = C
(C) S ∪ T ∪ C = S
(D) S ∪ T = S ∩



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Since square contains both triangle and circle, the union becomes same as square. so answer is C.
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