# In a quadrilateral ABCD,AB=30m,BC=15m,CD=30m,AD=15m and BD=35m.Find the area of quadrilateral?

by tenzk06

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by tenzk06

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AB=30m BC=15m CD=30m AD=15m

as opposite sides are equal, therefore, it is a rectangle.

diagonal BD divides it into two equal parts.

now, in ΔABD, let AB=30m=base

let AD=15m=height

thus, area ΔABD= 1/2 × base × height

= 1/2 × 30 × 15 m²

= 15 × 15 m²

area ΔABD= 225 m²

similarly, in ΔBCD, let DC=30m=base

let BC=15m=height

thus, area ΔBCD=area ΔABD=225m²

now, area quad. ABCD= area ΔABD + area ΔBCD

= 225m² + 225m²

thus, area quad. ABCD= 450m²

So it is a rectangle. We know area of a rectangle is . In these measurements, it is .