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If the system of equations x+y=3, y+z=5 , z+x=4 , x+y+kz=6 is consistent, then k equals

A) -1 B) 1 C) 2 D) 0
the answer is option B please explain me as fast as you can


Given that x+y=3,y+z=5,z+x=4 Therefore on adding it, we get 2(x+y+z)=12 .SOx+y+z=6
Now put x+y=3 in above equation to get 3+z=6 So z=3 Now, put value of x+y and z in the last given equation of ques, we get x+y+kz=6. \\ 3+k(3)=6 \\ 3k=3 \\ k=1
1 5 1
Thank's alot please answer my other questions
Link Plz
http://brainly.in/question/13263 this is one of my links i will send remaining links
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