Answers

2015-06-21T13:41:25+05:30
Sin(α+β) = sinαcosβ + cosαsinβ 
             = (1/2×1/3) + (√3/2 × 2√2/3)
             = 1/6 + √(2/3)
so (α+β) = sin⁻¹ (1/6 + √(2/3))
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