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Putting x=1, we see that the equation is satisfied. So 1 is a root of the equation. This is verification. In fact, you can find the conditions when 1 will be a root of the general quadratic equation Ax2+Bx+C=0, by, x=−B±B2−4AC√2A=1, B2−4AC=(2A+B)2, B2−4AC=4A2+B2+4AB, 4A(A+B+C)=0, A+B+C=0, where the last equality comes from the fact that in a quadratic equation, A is non-zero. So 1 is a root if and only if the sum of the coefficients is 0. (Again this can be verified by putting x=1 in the general equation directly.)
1 5 1
OMG! I'm sorry but it's not at all legible...I am unable to understand anything. Umm.....use the ENTER key please!
Hey! Wait! I got it but..... in the last step isn't it -4a(a=b=c)=0??
Nah-ah! I dind't understand what u said...but thanks for the help!
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