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  • Brainly User
2015-06-25T15:09:39+05:30
If you wanted values of x, y, this might be the answer
(x^3-216)-2(2y)(2y+9x)=0 \\
(x^3-6^3)-2(x-6)(10x-6)=0 \\
(x-6)[(x^2+6x+36)-20x+12]=0 \\
x^2-14x+48=0 \ \ or \ \ x=6
(x-6)(x-8)=0 \ \ or \ \ x=6.
Hence (x, y)=(6, 0) \ \ or \ \ (8, 1)
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