Answers

2015-06-27T08:27:31+05:30
Let the angles be x, y and z then
x+y+z=180
°
A/Q-
Case I: x+y=80°
               x=80°-y------------(1)
Case II: x-y=20°
              x=20°+y---------(2)
On comparing equation (1) and (2)
            80
°-y=20°+y
             
2y=80°-20°
                 y=60
°/2
                 y=30
°
         Then x=80°-30°
                 x=50°
We know that x+y+z=180°
           80°+z=180°
                 z=180°-80°
                 z=100°
So, The angles are 30°, 50° and 100°.
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2015-06-27T09:07:05+05:30
The sum of two angles is 80^0. We know that all the three angles of  a triangle adds up to 180. One of them is 20. So subtract.

80-20=60  
180-80=100 

Therefore the angles are 20,60 and 100.
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