Answers

2015-06-28T12:13:14+05:30
The required number:
HCF of 156,208 and 260:
=52
⇒The maximum number of students is 52.
Number of buses required:
 \frac{156+208+260}{52}
 \frac{624}{52}
⇒[tex]12[tex]
Ans:Maximum number of students is 52 and the minimum number of buses is 12.
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