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ABC is a right triangle right angled at B let B and E be any points on AB and BC respectively prove thatAE²+CD²=AC²+DE² plz as fast as you can



The Brainliest Answer!
AE^2+CD^2 = AB^2+BE^2      +    BD^2+BC^2= AC^2+  DB^2+BE^2= AC^2+DE^2
2 3 2
thnq for giving this wonderful reply
welzz :)
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