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Let the required fraction be x.
According to the sum,
 x-\frac{3}{11}= \frac{11}{3}  -x
x+x= \frac{3}{11} + \frac{11}{3}
2x= \frac{3*3+11*11}{33}
2x= \frac{130}{33}
x= \frac{130}{33*2} =1 \frac{32}{33}
Ans:The required fraction is 1 \frac{32}{33} .
0 0 0
The answer is 65/33
Plz tell me how should I find the answer
See , the number lies between 3/11 and 11/3 in such a way that x-3/11=11/3-x
Thanx so much
your welcome
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