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X+y = 29 7(x-y)=4*29=116 7x-7y = 116 7x+7y=203 solving these two 14x =319 x = 22.78 y= 6.22

find 2 numbers whose sum is 29 and seven times difference is equal to four times of their sum? solution: let the numbers be x and y . therefore , x+y = 29 ............( 1 )(given) 7 (x-y) = 4 (x+y) .......... (2) (given) From 1 and 2 , we get 7 (x - y) = 4 *29 7 (x -y) = 116 7x - 7y = 116 ............ (3) multiply b/s of 1 by 7 , we get 7x + 7y = 203 ............ (4) Adding 3 and 4 , we get 14x = 319 x = 319 /14

substitute x in 1 , we get 319 /14 + y = 29 y = 29 -319/14 = 29*14 - 319 /14 = 406 - 319 /14 = 87/14 hence two numbers are x=319/14 and y = 87/14