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Area of the square is 9,therefore side length of square is 3 units.
length of diagonal of suare is =sqrt{3^2+3^2} =3sqrt{2}
Area of circle=pi*[3sqrt{2}]^2
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We know the formula for the area of a circle is  \pi r^2 and for a square it is s^2.

The "r" is the diagonal. Now let's find the side of the square. It is (\sqrt{9}=3) . Use trigonometry to find the diagonal.

We know two angles, namely the right angle and the 45.We know on side and considering the right angle is  \alpha , the hypotenuse is the diagonal and the other side of the square is the opposite. Find the sine.

sin( \alpha )=sin(45)= 0.707(degrees)
h=sin( \alpha )*6

Therefore the diagonal is \sqrt{18} . Now put in the area

A=\pi r^2 \\ A=\pi\sqrt{18}^2 \\ A=18\pi \\ A=56.54

The Area is 56.54 or 18\pi .


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