Answers

2015-07-03T08:35:54+05:30
It can be these:
(11-1)+(13-3)+(15-5)=30
15+9+(7-1)=30
3!+15+9=30
15 + 13 + (11-9)/(7-5)*(3-1) = 30
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2015-07-03T11:51:49+05:30
There are multiple answers to this question. Let me show you how.The answer to this question can be obtained by changing the base of the system.For the uninformed, every number system has a base. Some of them are as follows:Decimal system : Base is 10 Binary system : Base is 2 Octal system : Base is 8::Now lets see how this base works.Lets take the Decimal system for an example:Suppose we want to know how is the number 100 written with the help of bases. So write down the number hundred as shown below. Then assign positions starting with 0 and increasing by one to the digits from left to right. So in this way, the 0 at unit's place get the position 0. The 0 at ten's place get the position 1 and the 1 at hundred's place get the position 2. Number =  1          2         1 Positions  - 2nd    1st      0th   Now evaluate like I have shown below:100 = 1(unit digit) x 10^0(unit's position) + 2(digit at ten's place) x 10^1(ten's position) + 1(digit at hundred's place) x 10^2(hundred's position). = 1 + 20 + 100 = 121Now, this can be applied to other base systems as well.Lets take base 17.The number 30 in base 17 becomes: 0 x 17^0 + 17 x 3^1 = 51 The number 13 in base 17 becomes: 1 x 17^1 + 3 x 17^0 = 20 The number 15 in base 17 becomes: 1 x 17^1 + 5 x 17^0 = 22 The number 9 in base 17 becomes: 9 x 17^0 = 9 Hence in base 17,   22+20+9 = 51In this way, we can see that as we change the base of the system, there are multiple answers possible.This problem is not solvable in Decimal system, where as we all know, summation of 3 odd numbers cannot give an even number.An interesting fact about this question: This was asked in the IAS examination and only 5 people were able to answer it.
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