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If root3 tan theta = 3 sin theta, then prove that sin^2 theta - cos^2 theta = 1/3

is it cube root of tan θ
or square root of tan θ
square root of 3 tan theta
here only root3 and tan theta or root3 tan theta
under root 2 tan theta



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Squaring both sides 3tan theta =9 sin^2theta Tan theta = 3 sin^2 theta Sin theta / cos theta = 3 sin^2 theta 1/3= sin theta cos theta I think there is some thing wrong in the question
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