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x² = (x-2)²

x² = x² + 4 - 4x

x =1

put x = 1 in first curve

y = 1

hence point = (1,1)

y = x²---------(1)

y = (x -2)² -------------(2)

dy/dx = 2x

dy/dx = 2 let m1 (at point (1,1))

dy/dx = 2(x-2)

dy/dx = -2 let m2 (at point (1,1))

tan Ф = (m1 - m2)/(1 + m1*m2) (Ф = angle between curves at point of intersection)

tan Ф = 4/ -3

Ф = tan^-1(-4/3)