Answers

2015-07-09T18:29:37+05:30
6=2*3
8=2*2*2
12=2*2*3
So the number must be divisible by 8 and the sum of its digits must be divisible by 3.
Greatest 3 digit number=999
By moving backwards constantly by trial and error method we get the following answer:984.
2 3 2
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