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The resistance of two conductor in series is 40 ohm & the resistance 6.4 ohm when connected in parallel. Find the resistance of individual conductor



Req in series = R1+R2=40+4+=80ohm
a resistance of 6.4 ohm is connected in parallel then 
then Req=R1R2/R!+R2
=5.92 ohm
approximately 6 ohm  is the net resistance of this individual circuit

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x+ y =40 & 1/x+1/y=1/6.5 and then solve it linear equation in two variable
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no lamba its about 10 line
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R1=32 and r2=8
r the individual resistance
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