Answers

2015-07-12T21:15:14+05:30
Principle:I2 is soluble in ethyl alcohol (C2H5OH) while NH4Cl is not.
Process 1 : Dissolution in a special solvent,i.e.Ethyl alcohol.

Iodine will dissolve within the solvent and NH4Cl crystals will be found floating on the surface of the liquid.

Process 2:Filtration

The mixture will be filtered and NH4Cl will be obtained on the filter paper.

Process 3:Evaporation

The subsequent filtrate will be evaporated to get the precipitate of Iodine.

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  • Brainly User
2015-07-12T21:43:11+05:30
We can separate by evaporation and filtration
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