# Please solve with steps: Father’s age is equal to the combined age of his four children. In 10 years, his age will be 2/3 of the sum of their ages. Find the age of the father.

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father's age=F

A+B+C+D=F

After 10 years

F+10=2/3 X (A+10+B+10+C+10+D+10)

F+10=2/3 X (A+B+C+D+40)

F+10=2/3 X (F+40) {as F=10}

F+10=(2F+80)/3

3(F+10)=2F+80

3F+30=2F+80

3F-2F=80-30