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= 3² + 1²

⇒ √10 = √(3² + 1²)

So √10 will be the hypotenuse of a right angled triangle with base 3 and altitude 1.

Steps:

1. Draw a line segment AB of length 3units with A at 0.

2. At point B, draw a line perpendicular to AB and cut a length of 1 unit.

3. Mark that point as C.

4. Join AC. Since AB was 3 units and BC was 1 unit, AC is √10 units.

5. Now extend line AB. Taking A as centre and AC as radius, draw an arc to cut the extended line AB and mark the point as D.

6. D is the point at √10.