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A motorcycle of mass 2000 kg is moving over a horizontal road with uniform velocity. If this motorcycle as to be stopped with a negative acceleration of

1.5m/sec, then what is the force of friction between the tyres of motorcycle and the road?


Acceleration, a = -1.5 m/s²
mass, m = 2000 kg

force = ma = 2000×(-1.5) = -3000N

So force is 3000N acting in the opposite direction to the motion.
(negative sign shows that it is acting opposite to the motion of object)
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