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Let the resistance be R1 and r2 in series.....r1+ r2= 108 ohm in parallel....r1r2/r1+r2 = 27 ohm r1r2 = 27 * 108 = 2916 R1-r2 = √ ( r1+r2)² - 4 r1r2 = √ 11664 - 11664 = 0 r1 = r 2 r1+r2 = 108 2r = 108 r = 54 ohm

there are two individual resistances....u have to find each of them....in parallel they are r1+r2/r1r2 not r1r2/r1+r2

when a number of resistors are connected in parallel, the sum of the reciprocal of the resistance of the individual resistors is equal to the reciprocal of the effective resistance of the combination.

Here you have to solve this question by solving quadratic equation...!

Given that when connected in parallel, the resultant resistance R(p) = r1 + r2 = 27 ohms and when connected in series, the resultant resistance R(e) = r1 + r2 = 108 ohms ..(1)