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Compute the (i) distance travelled and (ii) displacement made by

the student when he travels a distance of 4km eastwards and
then a further distance of 3 km northwards.
he would travel a DISTANCE of 7 km(4 km + 3 km)
and he has been displaced by or makes a displacement of 5 km
plz tell ur class and board .........and i would explain accordingly.........:)


Distance travelled = 4+3 = 7Km.
displacement = shortest distance between two points
                   = √(4²+3²)
                    = √25
                    = 5Km.
0 0 0
(i)distance=4+3=7 km
                         =(5^2)^1/2=5 km
0 0 0
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