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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

the resultant resistance of two resistance wires in series
combination is 108 ohm and in parallel combination is 24 ohm. find the
value of individual resistance? Solution: Let the resistances of two wires be r1 and r2 . According to Question , Equivalent Series resistance = 108 r1+r2 = 108 ........................(1) Equivalent Parallel resistance = 24 1/r1+1/r2 = 1/24 r1+r2/r1r2 =1/24 or 24 (r1+r2) = r1r2 Using equation 1 , we get 24(108) = r1r2 2592 = r1r2 or r1r2 = 2592 or r1 = 2592 /r2 ....................... (2) Using equation 2 in equation 1 ,we get 2592 /r2 +r2 = 108 2592 +r2² =108r2 r2² - 108r2 +2592 = 0 Now we have to solve the above quadratic equation here a=1 , b= -108 and c= 2592 d = -b +-√(b² - 4ac)/2a = -(-108)+-√((-108)² - 4*1*2592) /2*1 =108 +-√(11664 - 10368 ) / 2*1 =108 +-√1296 / 2 =108+-36 /2 = 108+36 / 2 or 108-36/2 = 142 /2 or 72/2 = 71 or 36 Let me take it as 36 hence r2 = 36 Substitute r2 = 36 in equation 1 , we get r1 +36 = 108 r1 = 108 - 36 r1 = 72

Hence the two resistance are 36 and 72 !! Hope This helps You !! If U feel this helpful !! Please rate as best!!