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## Answers

Change in momentum(Δp)=Δ(mv)

mass will only change when the speed of this particular mass is near the speed of light So,

for c being very very large than the v

Δp=mΔv or m(v-u)

Now the rate of change of momentum Δp/t=m(v-u)/t

Δp/t=m×a

**As acceleration(a)=(v-u)/t**

Δp/t=Force(F)

**As force=m×a**

F=ma=Δp/t

**Hence ,The rate of change of momentum is equal to the force applied.**

The rate of change of momentum is directly proportional to the force applied to body.

The rate of change of momentum is directly proportional to the force applied to body.

initial velocity = u

final velocity = v

time taken = t

change in momentum (Δp) = pf-pi

= mv -mu

rate of change of momentum = (mv-mu)/t

⇒ F α (mv-mu)/t

⇒ F α [m(v-u)]/t

⇒ F α ma

⇒ F = kma

Here k = proportionality constant.