Answers

2015-07-28T14:24:01+05:30
Let f(x)=x^3-3 x^2+x+2
     q(x)=x-2
     r(x)=-2 x+4
     g(x)=?
we know that,
f(x)=g(x)*q(x)+r(x)
g(x)=[f(x)-r(x)]/q(x)
    = (x^3-3 x^2+x+2+2 x-4)/x-2
    =(x^3-3 x^2+3 x-2)/x-2
    =x^2-x+1
The value of g(x) is x^2-x+1
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