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Given P = (-5, 2) A = (a, 0) B = (0, b) Let m:n = 2:3 (ratio in which P divides AB) W.K.T., P = ((mx2+nx1)/(m+n) , (my2+ny1)/(m+n)) P = ((2(0)+3(a))/(2+3) , (2(b)+3(0))/(2+3)) P = (3a/5 , 2b/5) By comparing P = (-5, 2) and P = (3a/5, 2b/5) We get a = -25/3 b = 5 Therefore, A = (-25/3 , 0) B = (0, 5)