Answers

2014-06-05T18:12:32+05:30
D/dxsin^-1(x-1/x+1)
suppose (x-1/x+1) is p
and
d/dxsin^-1x=1/ \sqrt{1-x^2}
so
d/dxsin^-1p
1/ \sqrt{1-p^2} *d/dxp
substituting the value of p
[x+1]/ 2\sqrt{x} *d/dx x-1/x+1
x+1/ 2\sqrt{x} *[(x+1)*1-(x-1)*1]/(x+1)^2
1/ (x+1) \sqrt{x}
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