Answers

2015-08-02T19:46:24+05:30
Initial momentum of man=m*v=60*18=1080 kg m/s
Initial momentum of train bogey=m*v=500*0=0 kg m/s      [1 quintal=100 kg]
total initial momentum of man and train bogey=(1080+0)kg m/s =1080 kg m/s 
According to conservation of momentum
Total initial momentum=Total final momentum
1080=(M+m)v
1080=(60+100)v
1080=160v
6.75m/s=v
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