Particle is dropped from the height of 20 m from ground. A constant force acts on the particle in horizontal direction due to which acceleration of the particle become 6m/s. Find the horizontal displacement of the particle till it reaches ground
Answer is 12 m
Please solve this numerical

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Answers

2015-08-04T00:51:50+05:30

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The equations that are relevant are :  (in horizontal and vertical directions)
       v =  u + a t
       v² = u² + 2 a s
       s = (v +u)/2  * t
       s = u t + 1/2 a t²

Horizontal acceleration does not affect the flight in the vertical direction.

vertical flight:
         height h = u t + 1/2 g t²
        20 =   0  + 1/2 g * t²          =>  time of flight =  t² = 20 * 2 / 10
             t = 2 sec.

In 10 seconds, the particle will travel horizontally:  The displacement is :
           s = u t + 1/2 a t² = 0 + 1/2 * 6 * 2²  = 12 meters

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I forget to put initial velocity of particle zero