Answers

2015-08-05T05:06:02+05:30
Given :
molality is 3 which means 3 moles of solute present in 1000 g of water.
Therefore, 
No.of moles of NaOH = 3
No.of moles of water= mass of water/molar mass of water.
1000/18 = 55.5 moles
mole fraction of solvent = moles of solvent/moles of solute  + moles of solvent
55.5/3+55.5 = 0.051 

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