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The line parallel to 2x+3y-7 = 0 is of the form 2x+3y+k = 0. The perpendicular distance from centre to the tangent is equal to radius of the circle. Center of given circle is (0,0) Radius = √13 The perpendicular distance = [|2(0)+3(0)+k|]/√4+9 But we know perpendicular distance = radius |k|/√13 = √13 |k|= 13. k = + 13 The equation of tangents are 2x+3y+13 = 0 and 2x+3y-13 = 0