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  • Brainly User
2014-06-06T10:54:04+05:30
It will be at (B) W/2 at a depth halfway to the centre.
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  • Brainly User
2014-06-06T11:02:39+05:30

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G' = g( 1-d/R ) 
Now d that is depth is R/2
substituting d
g' = g(1-R/2R )
g' = g/2
multiplying both sides by m
mg' = mg/2
weight is nothing but mass * gravity 
Weight at halfway depth = W/2

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