Answers

2015-08-14T21:17:18+05:30
N-propyl bromide reacts with alkaline KOH undergoes dehydro halogination to form propene.

CH3CH2CH2-Br + alc.KOH → CH3CH=CH2

propene reacts with HBr in the presence of peroxide to form isopropyl bromide. this ANTI MARKOWNIKOFFS addition

CH3CH=CH2 + HBr + peroxide → CH3CH2BrCH3
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