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A cricket ball of mass 150 g moving at

36 m s^{-1} strikes a bat and
returns back along the same line at 21 m^{s -1} . What is the
change in momentum produced? If the bat remains in contact
with the ball for 1/20 s, what is the average force exerted in



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Mass = 0.15 kg
U= 36mps
V= -21mps [rebound]
So, change in momentum = mv-mu=0.15 [36-(-21)]=0.15*57=8.55
Force = Rate of change of momentum = change in p/t = 8.55 / (1/20) =171 N
Please recheck in case of calculation mistakes

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