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question refers to class 11th maths..chapter Limits and derivatives......We have to find the limt of this qustion....Lim(x-0) (x+1)^5 - 1 / x . I got

solution to this qustion on topperlearnign bu i have doubt....

Solution Says - Put x+1 = y so that y -> as x - 0[my question is why do they put x+1 = y ]

lim(x-0) (x+1)^5 - 1 / x = lim(y-1) y^5 -1 / y-1
lim(y-1) y^5-1^5 / y-1
5.1 ^ 5-1



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If you put x=y in the given equation it would make no change to the equation as y will take place of x only, Thus what you get will be
lim_{y \to \ 0} [(y+1)^5 -1]/y which is same as your given  equation.
For finding a solution to any question the logic is to convert the question into general (predefined forms) which we have already learned.
The asked limit looks alot similar to the formula :
 \lim_{x \to \(a} [x^n-a^n]/x-a  n a^{n-1}
So, for converting the above format in this predefined format we put x+1=y
Now  {x \to \(0}  \\ {y \to \(1} 
So we can write, 
 \lim_{y \to \(1} (y^5-1)/(y-1)
Here a=1, n=5 so the solution is 5[1^{5-1}] = 5
0 0 0
It is common sense that to solve the limits you have to convert the question to a known form which you can solve. to do exactly that you have to do the operation that has been suggested.
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