# 1 mole of Co2 gas is mixed with 1 mole of So2 gas find gama for the mixture?urgenttttt pleaseeeeee

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by crmail

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by crmail

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CO2 : n1 = 1 mole M1 = molar mass = 44 gm/mole mass m1 = 44 gm

SO2 : n2 = 1 mole M2 = 64 gm/mole mass m2 = 64 gm

total mass of mixture = m = m1 + m2 = 108 gm

mole fractions nf1 = 1/2 and nf2 = 1/2

mass fractions: mf1 = 44/108 = 11/27 mf2 = 64/108 = 16/27

molar mass of the mixture = M = nf1 * M1 + nf2 * M2

Mm = 1/2 * 44 + 1/2 * 64 = 54 gm/Mole

Specific heats at constant pressure Cp: (to find from some tables or use formulas)

Cp1 : of CO2: 0.839 J/gm-K Cp2 of SO2 : 0.644 J/gm-K

Cp for the mixture = mf1 * Cp1 + mf2 * Cp2

*Cpm = 11/27 * 0.844 + 16/27 * 0.644 = 0.7255 J/gm-K *

average gas constant Rm for the mixture = R / Mm

*Rm = (8.314 J/mol-K) / 54 J/gm-K = 0.1539 J/gm-K *

**Cv for the mixture Cvm = Cpm - Cvm = 0.5716 J/gm-K**

*Ratio of specific heats of mixture = γ_m = Cpm / Cvm = 1.2692 or 1.27 nearly*

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Ratio of specific heats for CO2 = γ = 1.289

SO2 = γ = 1.29

Ratio of specific heats for the mixture is nearly same as that of the individual gases..because their specific heats at constant pressure Cp values are close.

SO2 : n2 = 1 mole M2 = 64 gm/mole mass m2 = 64 gm

total mass of mixture = m = m1 + m2 = 108 gm

mole fractions nf1 = 1/2 and nf2 = 1/2

mass fractions: mf1 = 44/108 = 11/27 mf2 = 64/108 = 16/27

molar mass of the mixture = M = nf1 * M1 + nf2 * M2

Mm = 1/2 * 44 + 1/2 * 64 = 54 gm/Mole

Specific heats at constant pressure Cp: (to find from some tables or use formulas)

Cp1 : of CO2: 0.839 J/gm-K Cp2 of SO2 : 0.644 J/gm-K

Cp for the mixture = mf1 * Cp1 + mf2 * Cp2

average gas constant Rm for the mixture = R / Mm

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Ratio of specific heats for CO2 = γ = 1.289

SO2 = γ = 1.29

Ratio of specific heats for the mixture is nearly same as that of the individual gases..because their specific heats at constant pressure Cp values are close.