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x2=x+x+x+x+... (x  times)
[12=1;22=2+2;32=3+3+3 and so on]

Differentiating this equation wrt x, we get
2x=1+1+1+1+... (x times)
0 0 0
I've already read this somewhere
we solved it in our school this way so i thought to tell you this thing
OK thanks
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