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When the given equation is divided by (x+4) then we must the get the remainder as zero then we can say (x+4) is a factor of given equation.

x+4)x³+3x²-5x+36(x²+x-9

As the remainder is not equal to zero x+4 is not a factor of given equation.

By substituting we get -64 + 48 + 20 +36 whose value is not equal to zero there fore (x+4) is not a factor of given equation.