a car travelling at a speed of 54km/h is brought to rest in 90 seconds find accelaration and distance travelled by car before coming to rest?

by ameypaleeran

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a car travelling at a speed of 54km/h is brought to rest in 90 seconds find accelaration and distance travelled by car before coming to rest?

by ameypaleeran

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The final velocity(v) of the car is = 0 m/s

The time taken(t) by the car to come to rest = 90 seconds

We must find the acceleration(a) and displacement(s) covered by the car

From v = u+at .we find acceleration of the car .

By substituting in the equation we get

0 = 15 + a(90)

a = - 15/90

a = -1/6 m/s²

The displacement of the car is given by

v²-u² = 2as

0²-15² = 2*(-1/6)s

225 = (1/3)s

s= 225*3 =675 m.

finial speed = 0

time = 90s

v = u + at

0 = 15 + 90a

a = -1/6

let distance = s

v² = u² + 2as

0 = 15² - 2*1/6*s

s = 225*3

s = 675 m