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If y^2=4ax is parabola then given point satisfies this
focus is (a,0)=>(-5,0)
1 5 1
By using the general eq. y^2=4ax,we get a=-5 by substituting the given point (-5,10).
the focal point is (a,0)=(m,n)=(-5,0)
(if the parabola is to the ryt of y-axis)
[m,n]=(5,0) if the parabola is to the left of y-axis.
0 0 0
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