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Dividing +100 by n+10
with the help of long division we get 
−10n+100 as a quotient
and - 900 as a remainder 
we know that
divisor * quotient +remainder=dividend
 n+10(−10n+100)-900 =+100.....1
dividing equation 1  by n+10 we get
+100/ n+10= (−10n+100) -900 /n+10
to maximize  900/n+10 should be minimise to lowest integer   which in this case is 1
0 0 0
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